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set-6

251. Which of the following is the faster logic?

$\text{TTL}$
$\text{CMOS}$
$\text{ECL}$
$\text{LSI}$

Show me the answer

Answer: 3. $\text{ECL}$

Explanation:

ECL (Emitter-Coupled Logic) is the fastest logic family due to its non-saturating operation.

252. If the input to a T-flip-flop is a 100 Hz signal, the final output of the three T-flip-flops in cascade is:

$1000 \text{ Hz}$
$333 \text{ Hz}$
$500 \text{ Hz}$
$12.5 \text{ Hz}$

Show me the answer

Answer: 4. $12.5 \text{ Hz}$

Explanation:

Each T-flip-flop divides the frequency by 2, so three flip-flops divide the frequency by ( 2^3 = 8 ), resulting in ( 100 \text{ Hz} / 8 = 12.5 \text{ Hz} ).

253. Which of the following memory is volatile memory?

Show me the answer

Explanation:

RAM (Random Access Memory) is volatile, meaning it loses its data when power is turned off.

254. -8 is equal to the signed binary number:

Show me the answer

Explanation:

In 8-bit signed binary, -8 is represented as 10001000.

255. De Morgan's first theorem shows the equivalence of:

Show me the answer

Explanation:

De Morgan's first theorem states that ( \overline{A + B} = \overline{A} \cdot \overline{B} ), which is equivalent to a NOR gate being the same as a bubbled AND gate.

256. The digital logic family which has the lowest propagation delay time is:

Show me the answer

Explanation:

ECL (Emitter-Coupled Logic) has the lowest propagation delay among the given options.

257. The device which changes from serial data to parallel data is:

Show me the answer

Explanation:

A demultiplexer converts serial data into parallel data.

258. A device which converts BCD to Seven Segment is called:

Show me the answer

Explanation:

A BCD-to-Seven Segment decoder converts BCD input into the corresponding Seven Segment display output.

259. In a JK Flip-Flop, toggle means:

Show me the answer

Explanation:

Toggling in a JK Flip-Flop means changing the output to the opposite state (from 0 to 1 or from 1 to 0).

260. The access time of ROM using bipolar transistors is about:

Show me the answer

Explanation:

The access time of ROM using bipolar transistors is typically in the nanosecond (nsec) range.

261. The A/D converter whose conversion time is independent of the number of bits is:

Show me the answer

Explanation:

Parallel conversion A/D converters have a conversion time that is independent of the number of bits.

262. When signed numbers are used in binary arithmetic, which notation has a unique representation for zero?

Show me the answer

Explanation:

In 2's complement representation, zero has a unique representation (all bits 0).

263. A hexadecimal odometer displays F52F. The next reading will be:

Show me the answer

Explanation:

The next reading after F52F is F530.

264. Most digital computers do not have floating-point hardware because:

Show me the answer

Explanation:

Floating-point hardware is expensive, so many systems rely on software for floating-point operations.

265. In digital ICs, Schottky transistors are preferred over normal transistors because of their:

Show me the answer

Explanation:

Schottky transistors have a lower propagation delay, making them faster.

266. The following switching functions are to be implemented using a Decoder:

( f_1 = \sum m(1, 2, 4, 8, 10, 14) ) ( f_2 = \sum m(2, 5, 9, 11) ) ( f_3 = \sum m(2, 4, 5, 6, 7) ) The minimum configuration of the decoder should be:

Show me the answer

Explanation:

A 4-to-16 line decoder is required to handle the given minterms.

267. A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for a change of state is:

Show me the answer

Explanation:

In a synchronous counter, all flip-flops change state simultaneously, so the maximum delay is equal to the propagation delay of one flip-flop (15 ns).

268. Words having 8-bits are to be stored into computer memory. The number of lines required for writing into memory are:

Show me the answer

Explanation:

An 8-bit word requires 8 lines for writing into memory.

269. In a successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter's output. This is done to:

Show me the answer

Explanation:

Adding an offset voltage of 1/2 LSB reduces the maximum quantization error.

270. The decimal equivalent of the binary number 11010 is:

Show me the answer

Explanation:

The binary number 11010 converts to the decimal number 26.

271. The 1's complement representation of the decimal number -17 using 8-bit representation is:

Show me the answer

Explanation:

The 1's complement of -17 is obtained by inverting all bits of the binary representation of 17.

272. The excess-3 code of the decimal number 26 is:

Show me the answer

Explanation:

The excess-3 code of 26 is obtained by adding 3 to each digit and converting to binary.

273. How many AND gates are required to realize ( Y = CD + EF + G )?

Show me the answer

Explanation:

Three AND gates are required for the terms ( CD ), ( EF ), and ( G ).

274. How many select lines will a 16-to-1 multiplexer have?

Show me the answer

Explanation:

A 16-to-1 multiplexer requires 4 select lines (since ( 2^4 = 16 )).

275. How many flip-flops are required to construct a decade counter?

Show me the answer

Explanation:

A decade counter counts from 0 to 9, requiring 4 flip-flops (since ( 2^4 = 16 \geq 10 )).

276. Which TTL logic gate is used for wired ANDing?

Show me the answer

Explanation:

Open collector outputs are used for wired ANDing because they allow multiple outputs to be connected together.

277. CMOS circuits consume power:

Show me the answer

Explanation:

CMOS circuits consume significantly less power than TTL circuits.

278. In a RAM, information can be stored:

Show me the answer

Explanation:

RAM allows users to write and rewrite data multiple times.

279. The hexadecimal number for ( (95.5)_{10} ) is:

Show me the answer

Explanation:

The decimal number 95.5 converts to the hexadecimal number 5F.8.

280. The octal equivalent of ( (247)_{10} ) is:

Show me the answer

Explanation:

The decimal number 247 converts to the octal number 367.

281. The chief reason why digital computers use complemented subtraction is that it:

Show me the answer

Explanation:

Complemented subtraction simplifies the handling of negative numbers in digital systems.

282. In a positive logic system, logic state 1 corresponds to:

Show me the answer

Explanation:

In positive logic, logic state 1 corresponds to a higher voltage level.

283. The commercially available 8-input multiplexer integrated circuit in the TTL family is:

Show me the answer

Explanation:

The 74151 is an 8-input multiplexer in the TTL family.

284. CMOS circuits are extensively used for on-chip computers mainly because of their extremely:

Show me the answer

Explanation:

CMOS circuits are preferred for on-chip computers due to their low power consumption.

285. The MSI chip 7474 is:

Show me the answer

Explanation:

The 7474 is a dual edge-triggered D flip-flop in the TTL family.

286. Which of the following memories stores the most number of bits?

Show me the answer

Explanation:

A 5Mx8 memory stores ( 5 \times 8 = 40 ) million bits, which is the largest among the options.

287. The process of entering data into a ROM is called:

Show me the answer

Explanation:

The process of entering data into a ROM is called programming.

288. When the set of input data to an even parity generator is 0111, the output will be:

Show me the answer

Explanation:

The input 0111 has an odd number of 1s, so the even parity bit is 0.

289. The number 140 in octal is equivalent to:

Show me the answer

Explanation:

The octal number 140 converts to the decimal number 96.

290. The NOR gate output will be high if the two inputs are:

Show me the answer

Explanation:

A NOR gate outputs 1 only when all inputs are 0.

291. Which of the following is the fastest logic?

Show me the answer

Explanation:

ECL (Emitter-Coupled Logic) is the fastest logic family.

292. How many flip-flops are required to construct a mod-30 counter?

Show me the answer

Explanation:

A mod-30 counter requires 5 flip-flops (since ( 2^5 = 32 \geq 30 )).

293. How many address bits are required to represent a 32K memory?

Show me the answer

Explanation:

A 32K memory requires ( \log_2(32768) = 15 ) bits, but 14 bits are sufficient for 16K, so 15 bits are needed for 32K.

294. The number of control lines for a 16-to-1 multiplexer is:

Show me the answer

Explanation:

A 16-to-1 multiplexer requires 4 control lines (since ( 2^4 = 16 )).

295. Which of the following requires refreshing?

Show me the answer

Explanation:

DRAM (Dynamic RAM) requires periodic refreshing to maintain data.

296. Shifting a register content to the left by one bit position is equivalent to:

Show me the answer

Explanation:

Shifting left by one bit is equivalent to multiplying the number by 2.

297. For a JK flip-flop with ( J = 1 ) and ( K = 0 ), the output after a clock pulse will be:

Show me the answer

Explanation:

When ( J = 1 ) and ( K = 0 ), the JK flip-flop sets the output to 1.

298. Convert decimal 153 to octal. The equivalent in octal will be:

Show me the answer

Explanation:

The decimal number 153 converts to the octal number 231.

Show me the answer

Explanation:

The binary number 1100 converts to the decimal number 12.

Show me the answer

Explanation:

The hexadecimal number FA converts to the binary number 11111010.

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251. Which of the following is the faster logic?

$\text{TTL}$
$\text{CMOS}$
$\text{ECL}$
$\text{LSI}$

Show me the answer

Answer: 3. $\text{ECL}$

Explanation:

ECL (Emitter-Coupled Logic) is the fastest logic family due to its non-saturating operation.

252. If the input to a T-flip-flop is a 100 Hz signal, the final output of the three T-flip-flops in cascade is:

$1000 \text{ Hz}$
$333 \text{ Hz}$
$500 \text{ Hz}$
$12.5 \text{ Hz}$

Show me the answer

Answer: 4. $12.5 \text{ Hz}$

Explanation:

Each T-flip-flop divides the frequency by 2, so three flip-flops divide the frequency by ( 2^3 = 8 ), resulting in ( 100 \text{ Hz} / 8 = 12.5 \text{ Hz} ).

253. Which of the following memory is volatile memory?

$\text{ROM}$
$\text{PROM}$
$\text{RAM}$
$\text{EEPROM}$

Show me the answer

Answer: 3. $\text{RAM}$

Explanation:

RAM (Random Access Memory) is volatile, meaning it loses its data when power is turned off.

254. -8 is equal to the signed binary number:

$10001000$
$10000000$
$00001000$
$1000000$

Show me the answer

Answer: 1. $10001000$

Explanation:

In 8-bit signed binary, -8 is represented as 10001000.

255. De Morgan's first theorem shows the equivalence of:

$\text{OR gate and Exclusive OR gate}$
$\text{NOR gate and Bubbled AND gate}$
$\text{NOR gate and NAND gate}$
$\text{NAND gate and NOT gate}$

Show me the answer

Answer: 2. $\text{NOR gate and Bubbled AND gate}$

Explanation:

De Morgan's first theorem states that ( \overline{A + B} = \overline{A} \cdot \overline{B} ), which is equivalent to a NOR gate being the same as a bubbled AND gate.

256. The digital logic family which has the lowest propagation delay time is:

$\text{ECL}$
$\text{CMOS}$
$\text{TTL}$
$\text{PMOS}$

Show me the answer

Answer: 1. $\text{ECL}$

Explanation:

ECL (Emitter-Coupled Logic) has the lowest propagation delay among the given options.

257. The device which changes from serial data to parallel data is:

$\text{Counter}$
$\text{Demultiplexer}$
$\text{Multiplexer}$
$\text{Flip-flop}$

Show me the answer

Answer: 2. $\text{Demultiplexer}$

Explanation:

A demultiplexer converts serial data into parallel data.

258. A device which converts BCD to Seven Segment is called:

$\text{Encoder}$
$\text{Multiplexer}$
$\text{Decoder}$
$\text{De-multiplexer}$

Show me the answer

Answer: 3. $\text{Decoder}$

Explanation:

A BCD-to-Seven Segment decoder converts BCD input into the corresponding Seven Segment display output.

259. In a JK Flip-Flop, toggle means:

$\text{Set } Q = 1 \text{ and } \overline{Q} = 0$
$\text{Set } Q = 0 \text{ and } \overline{Q} = 1$
$\text{Change the output to the opposite state}$
$\text{No change in output}$

Show me the answer

Answer: 3. $\text{Change the output to the opposite state}$

Explanation:

Toggling in a JK Flip-Flop means changing the output to the opposite state (from 0 to 1 or from 1 to 0).

260. The access time of ROM using bipolar transistors is about:

$1 \text{ sec}$
$1 \text{ psec}$
$1 \text{ msec}$
$\text{nsec}$

Show me the answer

Answer: 4. $\text{nsec}$

Explanation:

The access time of ROM using bipolar transistors is typically in the nanosecond (nsec) range.

261. The A/D converter whose conversion time is independent of the number of bits is:

$\text{Dual slope}$
$\text{Parallel conversion}$
$\text{Counter type}$
$\text{Successive approximation}$

Show me the answer

Answer: 2. $\text{Parallel conversion}$

Explanation:

Parallel conversion A/D converters have a conversion time that is independent of the number of bits.

262. When signed numbers are used in binary arithmetic, which notation has a unique representation for zero?

$\text{Sign-magnitude}$
$\text{2's complement}$
$\text{1's complement}$
$\text{9's complement}$

Show me the answer

Answer: 2. $\text{2's complement}$

Explanation:

In 2's complement representation, zero has a unique representation (all bits 0).

263. A hexadecimal odometer displays F52F. The next reading will be:

$F52F$
$F530$
$F53F$
$F530$

Show me the answer

Answer: 2. $F530$

Explanation:

The next reading after F52F is F530.

264. Most digital computers do not have floating-point hardware because:

$\text{Floating-point hardware is costly}$
$\text{It is slower than software}$
$\text{It is not possible to perform floating-point addition by hardware}$
$\text{No specific reason}$

Show me the answer

Answer: 1. $\text{Floating-point hardware is costly}$

Explanation:

Floating-point hardware is expensive, so many systems rely on software for floating-point operations.

265. In digital ICs, Schottky transistors are preferred over normal transistors because of their:

$\text{Lower propagation delay}$
$\text{Lower power dissipation}$
$\text{Higher propagation delay}$
$\text{Higher power dissipation}$

Show me the answer

Answer: 1. $\text{Lower propagation delay}$

Explanation:

Schottky transistors have a lower propagation delay, making them faster.

266. The following switching functions are to be implemented using a Decoder:

( f_1 = \sum m(1, 2, 4, 8, 10, 14) ) ( f_2 = \sum m(2, 5, 9, 11) ) ( f_3 = \sum m(2, 4, 5, 6, 7) ) The minimum configuration of the decoder should be:

$2-to-4 \text{ line}$
$4-to-16 \text{ line}$
$3-to-8 \text{ line}$
$5-to-32 \text{ line}$

Show me the answer

Answer: 2. $4-to-16 \text{ line}$

Explanation:

A 4-to-16 line decoder is required to handle the given minterms.

267. A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for a change of state is:

$15 \text{ ns}$
$45 \text{ ns}$
$30 \text{ ns}$
$60 \text{ ns}$

Show me the answer

Answer: 1. $15 \text{ ns}$

Explanation:

In a synchronous counter, all flip-flops change state simultaneously, so the maximum delay is equal to the propagation delay of one flip-flop (15 ns).

268. Words having 8-bits are to be stored into computer memory. The number of lines required for writing into memory are:

Show me the answer

Answer: 4. $8$

Explanation:

An 8-bit word requires 8 lines for writing into memory.

269. In a successive-approximation A/D converter, offset voltage equal to 1/2 LSB is added to the D/A converter's output. This is done to:

$\text{Improve the speed of operation}$
$\text{Reduce the maximum quantization error}$
$\text{Increase the number of bits at the output}$
$\text{Increase the range of input voltage that can be converted}$

Show me the answer

Answer: 2. $\text{Reduce the maximum quantization error}$

Explanation:

Adding an offset voltage of 1/2 LSB reduces the maximum quantization error.

270. The decimal equivalent of the binary number 11010 is:

$26$
$16$
$36$
$23$

Show me the answer

Answer: 1. $26$

Explanation:

The binary number 11010 converts to the decimal number 26.

271. The 1's complement representation of the decimal number -17 using 8-bit representation is:

$11101110$
$11001100$
$11011101$
$00010001$

Show me the answer

Answer: 1. $11101110$

Explanation:

The 1's complement of -17 is obtained by inverting all bits of the binary representation of 17.

272. The excess-3 code of the decimal number 26 is:

$01001001$
$10001001$
$01011001$
$01001101$

Show me the answer

Answer: 3. $01011001$

Explanation:

The excess-3 code of 26 is obtained by adding 3 to each digit and converting to binary.

273. How many AND gates are required to realize ( Y = CD + EF + G )?

Show me the answer

Answer: 2. $3$

Explanation:

Three AND gates are required for the terms ( CD ), ( EF ), and ( G ).

274. How many select lines will a 16-to-1 multiplexer have?

Show me the answer

Answer: 1. $4$

Explanation:

A 16-to-1 multiplexer requires 4 select lines (since ( 2^4 = 16 )).

275. How many flip-flops are required to construct a decade counter?

$10$
$4$
$3$
$2$

Show me the answer

Answer: 2. $4$

Explanation:

A decade counter counts from 0 to 9, requiring 4 flip-flops (since ( 2^4 = 16 \geq 10 )).

276. Which TTL logic gate is used for wired ANDing?

$\text{Open collector output}$
$\text{Tristate output}$
$\text{Totem Pole}$
$\text{ECL gates}$

Show me the answer

Answer: 1. $\text{Open collector output}$

Explanation:

Open collector outputs are used for wired ANDing because they allow multiple outputs to be connected together.

277. CMOS circuits consume power:

$\text{Equal to TTL}$
$\text{Twice of TTL}$
$\text{Less than TTL}$
$\text{Thrice of TTL}$

Show me the answer

Answer: 3. $\text{Less than TTL}$

Explanation:

CMOS circuits consume significantly less power than TTL circuits.

278. In a RAM, information can be stored:

$\text{By the user, number of times}$
$\text{By the user, only once}$
$\text{By the manufacturer, a number of times}$
$\text{By the manufacturer only once}$

Show me the answer

Answer: 1. $\text{By the user, number of times}$

Explanation:

RAM allows users to write and rewrite data multiple times.

279. The hexadecimal number for ( (95.5)_{10} ) is:

$(5F.8)_{16}$
$(2E.F)_{16}$
$(9A.B)_{16}$
$(5A.4)_{16}$

Show me the answer

Answer: 1. $(5F.8)_{16}$

Explanation:

The decimal number 95.5 converts to the hexadecimal number 5F.8.

280. The octal equivalent of ( (247)_{10} ) is:

$(252)_8$
$(367)_8$
$(350)_8$
$(400)_8$

Show me the answer

Answer: 2. $(367)_8$

Explanation:

The decimal number 247 converts to the octal number 367.

281. The chief reason why digital computers use complemented subtraction is that it:

$\text{Simplifies the circuitry}$
$\text{Is a very simple process}$
$\text{Can handle negative numbers easily}$
$\text{Avoids direct subtraction}$

Show me the answer

Answer: 3. $\text{Can handle negative numbers easily}$

Explanation:

Complemented subtraction simplifies the handling of negative numbers in digital systems.

282. In a positive logic system, logic state 1 corresponds to:

$\text{Positive voltage}$
$\text{Zero voltage level}$
$\text{Higher voltage level}$
$\text{Lower voltage level}$

Show me the answer

Answer: 3. $\text{Higher voltage level}$

Explanation:

In positive logic, logic state 1 corresponds to a higher voltage level.

283. The commercially available 8-input multiplexer integrated circuit in the TTL family is:

$7495$
$74154$
$74153$
$74151$

Show me the answer

Answer: 4. $74151$

Explanation:

The 74151 is an 8-input multiplexer in the TTL family.

284. CMOS circuits are extensively used for on-chip computers mainly because of their extremely:

$\text{Low power dissipation}$
$\text{Large packing density}$
$\text{High noise immunity}$
$\text{Low cost}$

Show me the answer

Answer: 1. $\text{Low power dissipation}$

Explanation:

CMOS circuits are preferred for on-chip computers due to their low power consumption.

285. The MSI chip 7474 is:

$\text{Dual edge-triggered JK flip-flop (TTL)}$
$\text{Dual edge-triggered D flip-flop (CMOS)}$
$\text{Dual edge-triggered D flip-flop (TTL)}$
$\text{Dual edge-triggered JK flip-flop (CMOS)}$

Show me the answer

Answer: 3. $\text{Dual edge-triggered D flip-flop (TTL)}$

Explanation:

The 7474 is a dual edge-triggered D flip-flop in the TTL family.

286. Which of the following memories stores the most number of bits?

$\text{A 5Mx8 memory}$
$\text{A 5Mx4 memory}$
$\text{A 1Mx16 memory}$
$\text{A 1Mx12 memory}$

Show me the answer

Answer: 1. $\text{A 5Mx8 memory}$

Explanation:

A 5Mx8 memory stores ( 5 \times 8 = 40 ) million bits, which is the largest among the options.

287. The process of entering data into a ROM is called:

$\text{Burning in the ROM}$
$\text{Changing the ROM}$
$\text{Programming the ROM}$
$\text{Charging the ROM}$

Show me the answer

Answer: 3. $\text{Programming the ROM}$

Explanation:

The process of entering data into a ROM is called programming.

288. When the set of input data to an even parity generator is 0111, the output will be:

$1$
$\text{Unpredictable}$
$0$
$\text{Depends on the previous input}$

Show me the answer

Answer: 3. $0$

Explanation:

The input 0111 has an odd number of 1s, so the even parity bit is 0.

289. The number 140 in octal is equivalent to:

$(96)_{10}$
$(90)_{10}$
$(86)_{10}$
$\text{None of these}$

Show me the answer

Answer: 3. $(86)_{10}$

Explanation:

The octal number 140 converts to the decimal number 96.

290. The NOR gate output will be high if the two inputs are:

$00$
$10$
$01$
$11$

Show me the answer

Answer: 1. $00$

Explanation:

A NOR gate outputs 1 only when all inputs are 0.

291. Which of the following is the fastest logic?

$\text{ECL}$
$\text{CMOS}$
$\text{TTL}$
$\text{LSI}$

Show me the answer

Answer: 1. $\text{ECL}$

Explanation:

ECL (Emitter-Coupled Logic) is the fastest logic family.

292. How many flip-flops are required to construct a mod-30 counter?

Show me the answer

Answer: 1. $5$

Explanation:

A mod-30 counter requires 5 flip-flops (since ( 2^5 = 32 \geq 30 )).

293. How many address bits are required to represent a 32K memory?

$10 \text{ bits}$
$14 \text{ bits}$
$12 \text{ bits}$
$16 \text{ bits}$

Show me the answer

Answer: 2. $14 \text{ bits}$

Explanation:

A 32K memory requires ( \log_2(32768) = 15 ) bits, but 14 bits are sufficient for 16K, so 15 bits are needed for 32K.

294. The number of control lines for a 16-to-1 multiplexer is:

Show me the answer

Answer: 3. $4$

Explanation:

A 16-to-1 multiplexer requires 4 control lines (since ( 2^4 = 16 )).

295. Which of the following requires refreshing?

$\text{SRAM}$
$\text{ROM}$
$\text{DRAM}$
$\text{EPROM}$

Show me the answer

Answer: 3. $\text{DRAM}$

Explanation:

DRAM (Dynamic RAM) requires periodic refreshing to maintain data.

296. Shifting a register content to the left by one bit position is equivalent to:

$\text{Division by two}$
$\text{Multiplication by two}$
$\text{Addition by two}$
$\text{Subtraction by two}$

Show me the answer

Answer: 2. $\text{Multiplication by two}$

Explanation:

Shifting left by one bit is equivalent to multiplying the number by 2.

297. For a JK flip-flop with ( J = 1 ) and ( K = 0 ), the output after a clock pulse will be:

$0$
$\text{High impedance}$
$1$
$\text{No change}$

Show me the answer

Answer: 3. $1$

Explanation:

When ( J = 1 ) and ( K = 0 ), the JK flip-flop sets the output to 1.

298. Convert decimal 153 to octal. The equivalent in octal will be:

$(231)_8$
$(431)_8$
$(331)_8$
$\text{None of these}$

Show me the answer

Answer: 1. $(231)_8$

Explanation:

The decimal number 153 converts to the octal number 231.

299. The decimal equivalent of $( (1100)_2 )$ is:

$12$
$18$
$16$
$20$

Show me the answer

Answer: 1. $12$

Explanation:

The binary number 1100 converts to the decimal number 12.

300. The binary equivalent of $( (FA)_{16} )$ is:

$10101111$
$10110011$
$11111010$
$\text{None of these}$

Show me the answer

Answer: 3. $11111010$

Explanation:

The hexadecimal number FA converts to the binary number 11111010.

$\text{ROM}$

$\text{PROM}$

$\text{RAM}$

$\text{EEPROM}$

Answer: 3. $\text{RAM}$

$10001000$

$10000000$

$00001000$

$1000000$

Answer: 1. $10001000$

$\text{OR gate and Exclusive OR gate}$

$\text{NOR gate and Bubbled AND gate}$

$\text{NOR gate and NAND gate}$

$\text{NAND gate and NOT gate}$

Answer: 2. $\text{NOR gate and Bubbled AND gate}$

$\text{ECL}$

$\text{CMOS}$

$\text{TTL}$

$\text{PMOS}$

Answer: 1. $\text{ECL}$

$\text{Counter}$

$\text{Demultiplexer}$

$\text{Multiplexer}$

$\text{Flip-flop}$

Answer: 2. $\text{Demultiplexer}$

$\text{Encoder}$

$\text{Multiplexer}$

$\text{Decoder}$

$\text{De-multiplexer}$

Answer: 3. $\text{Decoder}$

$\text{Set } Q = 1 \text{ and } \overline{Q} = 0$

$\text{Set } Q = 0 \text{ and } \overline{Q} = 1$

$\text{Change the output to the opposite state}$

$\text{No change in output}$

Answer: 3. $\text{Change the output to the opposite state}$

$1 \text{ sec}$

$1 \text{ psec}$

$1 \text{ msec}$

$\text{nsec}$

Answer: 4. $\text{nsec}$

$\text{Dual slope}$

$\text{Parallel conversion}$

$\text{Counter type}$

$\text{Successive approximation}$

Answer: 2. $\text{Parallel conversion}$

$\text{Sign-magnitude}$

$\text{2's complement}$

$\text{1's complement}$

$\text{9's complement}$

Answer: 2. $\text{2's complement}$

$F52F$

$F530$

$F53F$

$F530$

Answer: 2. $F530$

$\text{Floating-point hardware is costly}$

$\text{It is slower than software}$

$\text{It is not possible to perform floating-point addition by hardware}$

$\text{No specific reason}$

Answer: 1. $\text{Floating-point hardware is costly}$

$\text{Lower propagation delay}$

$\text{Lower power dissipation}$

$\text{Higher propagation delay}$

$\text{Higher power dissipation}$

Answer: 1. $\text{Lower propagation delay}$

$2-to-4 \text{ line}$

$4-to-16 \text{ line}$

$3-to-8 \text{ line}$

$5-to-32 \text{ line}$

Answer: 2. $4-to-16 \text{ line}$

$15 \text{ ns}$

$45 \text{ ns}$

$30 \text{ ns}$

$60 \text{ ns}$

Answer: 1. $15 \text{ ns}$

$1$

$4$

$2$

$8$

Answer: 4. $8$

$\text{Improve the speed of operation}$

$\text{Reduce the maximum quantization error}$

$\text{Increase the number of bits at the output}$

$\text{Increase the range of input voltage that can be converted}$

Answer: 2. $\text{Reduce the maximum quantization error}$

$26$

$16$

$36$

$23$

Answer: 1. $26$

$11101110$

$11001100$

$11011101$

$00010001$

Answer: 1. $11101110$

$01001001$

$10001001$

$01011001$

$01001101$

Answer: 3. $01011001$

$4$

$3$

$5$

$2$

Answer: 2. $3$

$4$

$5$

$3$

$1$

Answer: 1. $4$

$10$

$4$

$3$

$2$

Answer: 2. $4$

$\text{Open collector output}$

$\text{Tristate output}$

$\text{Totem Pole}$

$\text{ECL gates}$

Answer: 1. $\text{Open collector output}$

$\text{Equal to TTL}$

$\text{Twice of TTL}$

$\text{Less than TTL}$

$\text{Thrice of TTL}$

Answer: 3. $\text{Less than TTL}$

$\text{By the user, number of times}$

$\text{By the user, only once}$

$\text{By the manufacturer, a number of times}$

$\text{By the manufacturer only once}$

Answer: 1. $\text{By the user, number of times}$

$(5F.8)_{16}$

$(2E.F)_{16}$

$(9A.B)_{16}$

$(5A.4)_{16}$

Answer: 1. $(5F.8)_{16}$

$(252)_8$

$(367)_8$

$(350)_8$

$(400)_8$

Answer: 2. $(367)_8$

$\text{Simplifies the circuitry}$

$\text{Is a very simple process}$

$\text{Can handle negative numbers easily}$

$\text{Avoids direct subtraction}$

Answer: 3. $\text{Can handle negative numbers easily}$

$\text{Positive voltage}$

$\text{Zero voltage level}$

$\text{Higher voltage level}$

$\text{Lower voltage level}$

Answer: 3. $\text{Higher voltage level}$

$7495$

$74154$

$74153$

$74151$

Answer: 4. $74151$

$\text{Low power dissipation}$

$\text{Large packing density}$

$\text{High noise immunity}$

$\text{Low cost}$

Answer: 1. $\text{Low power dissipation}$

$\text{Dual edge-triggered JK flip-flop (TTL)}$

$\text{Dual edge-triggered D flip-flop (CMOS)}$

$\text{Dual edge-triggered D flip-flop (TTL)}$

$\text{Dual edge-triggered JK flip-flop (CMOS)}$

Answer: 3. $\text{Dual edge-triggered D flip-flop (TTL)}$

$\text{A 5Mx8 memory}$

$\text{A 5Mx4 memory}$

$\text{A 1Mx16 memory}$

$\text{A 1Mx12 memory}$

Answer: 1. $\text{A 5Mx8 memory}$

$\text{Burning in the ROM}$

$\text{Changing the ROM}$

$\text{Programming the ROM}$

$\text{Charging the ROM}$

Answer: 3. $\text{Programming the ROM}$

$1$

$\text{Unpredictable}$

$0$

$\text{Depends on the previous input}$

Answer: 3. $0$

$(96)_{10}$

$(90)_{10}$

$(86)_{10}$

$\text{None of these}$

Answer: 3. $(86)_{10}$

$00$

$10$

$01$

$11$

Answer: 1. $00$

$\text{ECL}$

$\text{CMOS}$

$\text{TTL}$

$\text{LSI}$

Answer: 1. $\text{ECL}$

$5$

$4$

$6$

$8$

Answer: 1. $5$

$10 \text{ bits}$

$14 \text{ bits}$

$12 \text{ bits}$

$16 \text{ bits}$

Answer: 2. $14 \text{ bits}$

$2$

$3$

$4$

$5$

Answer: 3. $4$

$\text{SRAM}$

$\text{ROM}$

$\text{DRAM}$

$\text{EPROM}$

Answer: 3. $\text{DRAM}$

$\text{Division by two}$

$\text{Multiplication by two}$

$\text{Addition by two}$

$\text{Subtraction by two}$

Answer: 2. $\text{Multiplication by two}$

$0$

$\text{High impedance}$

$1$

$\text{No change}$

Answer: 3. $1$

$(231)_8$

$(431)_8$

$(331)_8$

$\text{None of these}$

Answer: 1. $(231)_8$

299. The decimal equivalent of $( (1100)_2 )$ is:

$12$

$18$

$16$

$20$

Answer: 1. $12$

300. The binary equivalent of $( (FA)_{16} )$ is:

$10101111$

$10110011$

$11111010$

$\text{None of these}$

Answer: 3. $11111010$