1.4 Geometric Properties of Sections

1.4 Geometric Properties of Sections

Introduction to Geometric Properties

  • In structural engineering, the shape and distribution of material in a cross-section—not just the amount of material—determine its ability to resist bending, buckling, and torsion

  • These critical characteristics are quantified by the geometric properties of sections

  • These properties are fundamental to calculating stress, deflection, and stability in beams, columns, and other structural members

  • This unit explores the key geometric properties: axes of symmetry, the center of gravity, moment of inertia, and radius of gyration

  • This provides the mathematical tools to analyze built-up and standard structural shapes


1. Axes of Symmetry

  • Definition: An axis of symmetry is a line that divides a plane figure into two identical halves, each a mirror image of the other

  • The axis itself may be internal (within the figure) or external (outside the figure, like for a C-channel)

  • Types:

    • Vertical Axis of Symmetry: Divides the figure into left and right mirror images

    • Horizontal Axis of Symmetry: Divides the figure into top and bottom mirror images

  • Significance:

    • For sections with at least one axis of symmetry, the centroid (Center of Gravity) always lies on that axis

    • If a section has two perpendicular axes of symmetry, the centroid lies at their intersection

    • This is true for rectangles, circles, I-sections, etc

    • Symmetry simplifies the calculation of geometric properties

  • Examples:

    • Rectangle, Circle, I-section: Two perpendicular axes of symmetry

    • Angle (L-section), Channel (C-section), T-section: Only one axis of symmetry (or none for unequal legs)

    • Z-section: Has no axis of symmetry (point symmetry only)


2. Center of Gravity (Centroid)

  • Definition: The Centroid (C.G.) or Center of Gravity (for a uniform density lamina) is the unique point where the entire area of the figure can be assumed to be concentrated for the purpose of calculating the first moment of area

  • It is the geometric center of the shape

  • Concept: It is the average location of all the points in the shape

  • For a uniform density material, the centroid coincides with the center of mass

  • Location Coordinates: For a composite area made up of nn simple shapes with known individual areas AiA_i and centroids (xˉi,yˉi)(\bar{x}_i, \bar{y}_i)

    • xˉ=i=1nAixˉii=1nAi\bar{x} = \frac{\sum_{i=1}^{n} A_i \bar{x}_i}{\sum_{i=1}^{n} A_i}

    • yˉ=i=1nAiyˉii=1nAi\bar{y} = \frac{\sum_{i=1}^{n} A_i \bar{y}_i}{\sum_{i=1}^{n} A_i}

    • Where (xˉ,yˉ)(\bar{x}, \bar{y}) are the coordinates of the centroid of the composite area

  • Centroid of Built-up Plane Figures (Composite Sections):

    • Method: The composite section is divided into simple geometric shapes (rectangles, triangles, circles) whose areas and centroid locations are known

    • Procedure:

      • Divide the composite area into nn simple parts

      • Choose a convenient reference xx and yy axis

      • Calculate the area AiA_i and the centroid coordinates (xˉi,yˉi)(\bar{x}_i, \bar{y}_i) of each part relative to the reference axes

      • Apply the composite centroid formula above

    • Example: An I-section is divided into three rectangles (web and two flanges)

  • Centroid of Standard Steel Sections:

    • The centroid locations for standard rolled steel sections (I-beams, channels, angles, tees) are tabulated in steel section handbooks (like IS 808 or AISC manuals)

    • Key Point: For symmetrical sections (I-beam, channel about one axis), the centroid lies at the intersection of the axes of symmetry

    • For unsymmetrical sections (angle, channel about both axes), the centroid must be looked up or calculated

    • Example: For an unequal leg angle section (L 150 x 90 x 10), the centroid is not at the intersection of the center lines of the legs

    • It is closer to the larger leg


3. Moment of Inertia (Second Moment of Area)

  • Definition: The Moment of Inertia (II) of a plane area about an axis is a measure of its geometric stiffness or resistance to bending and deflection about that axis

  • It depends on both the shape of the area and the axis about which it is computed

  • Physical Significance:

    • It quantifies how the area of a cross-section is distributed relative to a given axis

    • A larger moment of inertia for a given area means the material is spread farther from the axis, resulting in greater bending stiffness

    • In the flexure formula, bending stress σ\sigma is inversely proportional to II

    • σ=MyI\sigma = \frac{My}{I}

    • Where MM is bending moment and yy is distance from neutral axis

  • Formulas:

    • About Centroidal Axes: For a shape with area AA

    • Rectangle (width bb, depth dd)

      • Ixx=bd312I_{xx} = \frac{bd^3}{12} (about horizontal centroidal axis)

      • Iyy=db312I_{yy} = \frac{db^3}{12} (about vertical centroidal axis)

    • Circle (diameter DD)

      • Ixx=Iyy=πD464I_{xx} = I_{yy} = \frac{\pi D^4}{64}

    • Triangle (base bb, height hh)

      • Ibase=bh312I_{base} = \frac{bh^3}{12} (about base)

  • Parallel Axis Theorem (Transfer Formula):

    • Purpose: To calculate the moment of inertia about any axis parallel to a known centroidal axis

    • Formula: I=Ic+Ad2I = I_c + A d^2

    • Where:

      • II = Moment of inertia about the new parallel axis

      • IcI_c = Moment of inertia about the centroidal axis parallel to the new axis

      • AA = Area of the shape

      • dd = Perpendicular distance between the two parallel axes

    • Application: This theorem is essential for finding the moment of inertia of composite/built-up sections

  • Moment of Inertia of Composite/Built-up Sections:

    • Procedure:

      • Divide the composite section into simple parts

      • Find the centroid of the entire composite section (as described in Section 2)

      • For each part, calculate its moment of inertia about its own centroidal axis parallel to the desired composite axis

      • Use the Parallel Axis Theorem to transfer this moment of inertia to the centroidal axis of the composite section

      • Ipart=Ic,part+Apartdpart2I_{part} = I_{c,part} + A_{part} d_{part}^2

      • Where dpartd_{part} is the distance between the centroid of the part and the centroid of the composite section

      • Sum the contributions from all parts

      • Itotal=(Ic,part+Apartdpart2)I_{total} = \sum (I_{c,part} + A_{part} d_{part}^2)

  • Polar Moment of Inertia (J):

    • Definition: Moment of inertia about an axis perpendicular to the plane (the z-axis)

    • Formula: J=Ixx+IyyJ = I_{xx} + I_{yy}

    • Significance: Measures resistance to torsion (twisting)

    • τ=TrJ\tau = \frac{T r}{J}

    • Where TT is torque


4. Radius of Gyration

  • Definition: The Radius of Gyration (kk) is a distance that represents how far from the axis the entire area of the section could be concentrated and still have the same moment of inertia

  • Mathematical Definition: It is the root-mean-square distance of the area elements from the axis

    • k=IAk = \sqrt{\frac{I}{A}}

    • Where II is the moment of inertia about the axis, and AA is the total area

  • Interpretation:

    • A larger radius of gyration indicates that the area is distributed farther from the axis, leading to greater bending stiffness and buckling resistance

    • It is a measure of the effectiveness of the cross-sectional shape in resisting buckling

  • Application in Column Design:

    • The slenderness ratio of a column, which determines its buckling load (Euler's formula), is defined as

    • λ=Lekmin\lambda = \frac{L_e}{k_{min}}

    • Where LeL_e is the effective length of the column, and kmink_{min} is the minimum radius of gyration (about the axis with the smallest kk)

    • Key Insight: For a given area, a shape with a higher minimum kk will have a lower slenderness ratio and thus a higher buckling load

  • Radius of Gyration for Common Sections:

    • Rectangle (about centroidal axis parallel to depth)

      • kxx=d12k_{xx} = \frac{d}{\sqrt{12}}

    • Circle

      • k=D4k = \frac{D}{4}


  • The geometric properties of sections—centroid, moment of inertia, and radius of gyration—are not merely abstract calculations

  • They are the fundamental link between the physical shape of a structural member and its engineering performance

  • The ability to compute these properties for complex, built-up sections using the principles of composite areas and the parallel axis theorem is an essential skill for designing efficient and safe beams, columns, and other structural elements

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