1.1 Sets
Detailed Theory: Sets
1. Basic Concepts and Definitions of Sets
1.1 What is a Set?
A set is a well-defined collection of distinct objects. The objects in a set are called its elements or members.
Key Characteristics:
Well-defined: It must be clear whether a particular object belongs to the set or not
Distinct: No element is repeated (each element appears only once)
Order doesn't matter: {1,2,3}={3,1,2}={2,3,1}
1.2 Notation and Symbols
Sets are denoted by capital letters: A,B,C,…
Elements are denoted by lowercase letters: a,b,c,…
Belongs to: a∈A means "a is an element of A"
Does not belong to: a∈/A means "a is not an element of A"
Such that: ∣ or : (colon) means "such that"
Example: A={1,2,3,4,5} Here, 3∈A but 7∈/A
1.3 Methods of Describing Sets
a) Roster/Tabular Method
All elements are listed within braces {}, separated by commas.
Examples:
Set of vowels in English alphabet: V={a,e,i,o,u}
Set of first five natural numbers: N5={1,2,3,4,5}
Set of even numbers between 1 and 10: E={2,4,6,8,10}
b) Set-Builder Method
Specifies a property that characterizes all elements of the set.
General Form: {x:P(x)} or {x∣P(x)} Read as: "The set of all x such that P(x) is true"
Examples:
{x:x is a natural number less than 6} This means: {1,2,3,4,5}
{x∈Z:−3<x<4} This means: {−2,−1,0,1,2,3}
{x:x=2n,n∈N} This means the set of all even natural numbers: {2,4,6,8,…}
1.4 Types of Sets
a) Empty/Null Set
A set with no elements. Denoted by ∅ or {}.
Important: {∅} is NOT an empty set. It's a set containing one element (which is the empty set).
Examples:
Set of natural numbers less than 1: ∅
{x:x2=−1,x∈R}=∅
b) Singleton Set
A set with exactly one element.
Examples:
A={5}
B={∅} (This is a singleton set containing the empty set)
Set of solutions of x+2=5: {3}
c) Finite Set
A set with finite number of elements. We can count all elements.
Examples:
A={a,b,c,d} has 4 elements
Set of days in a week: {Sunday,Monday,…,Saturday} has 7 elements
B={x:x is a prime number less than 10}={2,3,5,7} has 4 elements
d) Infinite Set
A set with infinite number of elements. We cannot count all elements.
Examples:
Set of all natural numbers: N={1,2,3,…}
Set of all integers: Z={…,−2,−1,0,1,2,…}
Set of all real numbers: R
e) Equal Sets
Two sets A and B are equal if they have exactly the same elements.
Notation: A=B
Criteria: A=B if and only if every element of A is in B and every element of B is in A.
Examples:
{1,2,3}={3,1,2}={2,1,3}
{x:x2−3x+2=0}={1,2}
{a,b,c}={a,b,d}
f) Equivalent Sets
Two sets are equivalent if they have the same number of elements (same cardinality).
Notation: A∼B
Important: Equal sets are always equivalent, but equivalent sets may not be equal.
Examples:
A={1,2,3} and B={a,b,c} are equivalent (both have 3 elements)
{1,2,3}∼{4,5,6} (both have cardinality 3)
2. Subsets and Power Sets
2.1 Subset
Set A is a subset of set B if every element of A is also an element of B.
Notation: A⊆B Read as: "A is a subset of B" or "A is contained in B"
Formal Definition: A⊆B if and only if x∈A⇒x∈B for all x
Examples:
{1,2}⊆{1,2,3,4}
N⊆Z⊆Q⊆R⊆C
Every set is a subset of itself: A⊆A
2.2 Proper Subset
A is a proper subset of B if A⊆B but A=B.
Notation: A⊂B or A⊊B
Examples:
{1,2}⊂{1,2,3}
∅⊂{1,2,3} (Empty set is a proper subset of every non-empty set)
{a,b}⊂{a,b,c}
2.3 Important Facts about Subsets
Empty set is subset of every set: ∅⊆A for any set A
Reflexive property: A⊆A for any set A
Transitive property: If A⊆B and B⊆C, then A⊆C
Antisymmetric property: If A⊆B and B⊆A, then A=B
2.4 Number of Subsets
If a set A has n elements, then:
Total number of subsets of A = 2n
Number of proper subsets of A = 2n−1
Proof: Each element has 2 choices: either be in a subset or not be in it. So for n elements, total possibilities = 2×2×⋯×2 (n times) = 2n.
Example: For A={a,b,c} (n=3):
Total subsets = 23=8
Proper subsets = 23−1=7
2.5 Power Set
The set of all subsets of a given set A is called the power set of A.
Notation: P(A) or 2A or P(A)
Properties:
∅∈P(A) and A∈P(A)
If A has n elements, then P(A) has 2n elements
A⊆B⇒P(A)⊆P(B)
Example: For A={1,2}: P(A)={∅,{1},{2},{1,2}}
Here, n(A) = 2, and n(P(A)) = 22=4
3. Universal Set and Complement
3.1 Universal Set
The set that contains all objects under consideration in a particular context.
Notation: Usually denoted by U or ξ
Properties:
Every set under consideration is a subset of U
The choice of universal set depends on the context
Examples:
In number theory: U=N or Z
In plane geometry: U=set of all points in the plane
For a survey of students: U=set of all students in the school
3.2 Complement of a Set
The complement of a set A is the set of all elements in the universal set U that are not in A.
Notation: A′ or Ac or A or U−A
Formal Definition: A′={x:x∈U and x∈/A}
Venn Diagram Representation: The region outside circle A but inside rectangle U.
Examples: Let U={1,2,3,4,5,6,7,8,9,10} and A={2,4,6,8,10} Then A′={1,3,5,7,9}
3.3 Properties of Complement
Complement Laws:
A∪A′=U
A∩A′=∅
Double Complement Law: (A′)′=A
Universal and Empty Set Complements:
U′=∅
∅′=U
De Morgan's Laws:
(A∪B)′=A′∩B′
(A∩B)′=A′∪B′
Proof of De Morgan's Law: (A∪B)′=A′∩B′ Let x∈(A∪B)′ ⇒x∈/(A∪B) ⇒x∈/A and x∈/B ⇒x∈A′ and x∈B′ ⇒x∈(A′∩B′) Thus, (A∪B)′⊆A′∩B′
Conversely, let x∈A′∩B′ ⇒x∈A′ and x∈B′ ⇒x∈/A and x∈/B ⇒x∈/(A∪B) ⇒x∈(A∪B)′ Thus, A′∩B′⊆(A∪B)′
Therefore, (A∪B)′=A′∩B′
4. Operations on Sets
4.1 Union of Sets
The union of sets A and B is the set of all elements that are in A, in B, or in both.
Notation: A∪B
Formal Definition: A∪B={x:x∈A or x∈B}
Venn Diagram: The entire shaded region of both circles.
Examples:
{1,2,3}∪{3,4,5}={1,2,3,4,5}
{a,b}∪{c,d}={a,b,c,d}
{x:x>0}∪{x:x<5}=R−{0} (all real numbers except 0)
4.2 Intersection of Sets
The intersection of sets A and B is the set of all elements common to both A and B.
Notation: A∩B
Formal Definition: A∩B={x:x∈A and x∈B}
Venn Diagram: The overlapping region of the two circles.
Examples:
{1,2,3}∩{3,4,5}={3}
{a,b,c}∩{c,d,e}={c}
{x:x>2}∩{x:x<5}={x:2<x<5}
Disjoint Sets
Two sets are disjoint if their intersection is empty.
Definition: A and B are disjoint if A∩B=∅
Examples:
{1,2} and {3,4} are disjoint
Set of even numbers and set of odd numbers are disjoint
4.3 Difference of Sets
The difference of sets A and B is the set of elements that are in A but not in B.
Notation: A−B or A∖B
Formal Definition: A−B={x:x∈A and x∈/B}
Important: A−B=B−A in general
Examples:
{1,2,3,4}−{3,4,5}={1,2}
{3,4,5}−{1,2,3,4}={5}
{a,b,c}−{b,c,d}={a}
Properties:
A−B=A∩B′
A−A=∅
A−∅=A
∅−A=∅
A−U=∅
4.4 Symmetric Difference
The symmetric difference of sets A and B is the set of elements that are in either A or B but not in both.
Notation: A△B or A⊖B
Formal Definitions:
A△B=(A∪B)−(A∩B)
A△B=(A−B)∪(B−A)
Venn Diagram: The non-overlapping parts of both circles.
Examples:
{1,2,3}△{3,4,5}={1,2,4,5}
{a,b,c}△{b,c,d}={a,d}
Properties:
Commutative: A△B=B△A
Associative: (A△B)△C=A△(B△C)
A△A=∅
A△∅=A
A△U=A′
5. Laws of Set Algebra
5.1 Commutative Laws
A∪B=B∪A
A∩B=B∩A
Proof of A∪B=B∪A: Let x∈A∪B ⇒x∈A or x∈B ⇒x∈B or x∈A ⇒x∈B∪A Thus, A∪B⊆B∪A
Similarly, B∪A⊆A∪B Therefore, A∪B=B∪A
5.2 Associative Laws
(A∪B)∪C=A∪(B∪C)
(A∩B)∩C=A∩(B∩C)
Example Verification: Let A={1,2},B={2,3},C={3,4} LHS: (A∪B)∪C=({1,2,3})∪{3,4}={1,2,3,4} RHS: A∪(B∪C)={1,2}∪{2,3,4}={1,2,3,4} LHS = RHS
5.3 Distributive Laws
A∪(B∩C)=(A∪B)∩(A∪C)
A∩(B∪C)=(A∩B)∪(A∩C)
Proof of A∪(B∩C)=(A∪B)∩(A∪C): Let x∈A∪(B∩C) Case 1: If x∈A, then x∈A∪B and x∈A∪C So x∈(A∪B)∩(A∪C)
Case 2: If x∈B∩C, then x∈B and x∈C So x∈A∪B and x∈A∪C Thus x∈(A∪B)∩(A∪C)
Therefore, A∪(B∩C)⊆(A∪B)∩(A∪C)
Conversely, let x∈(A∪B)∩(A∪C) Then x∈A∪B and x∈A∪C
If x∈A, then x∈A∪(B∩C) If x∈/A, then from x∈A∪B, we get x∈B And from x∈A∪C, we get x∈C So x∈B∩C, hence x∈A∪(B∩C)
Therefore, (A∪B)∩(A∪C)⊆A∪(B∩C)
Thus, A∪(B∩C)=(A∪B)∩(A∪C)
5.4 Identity Laws
A∪∅=A
A∩U=A
5.5 Complement Laws
A∪A′=U
A∩A′=∅
5.6 Idempotent Laws
A∪A=A
A∩A=A
5.7 Absorption Laws
A∪(A∩B)=A
A∩(A∪B)=A
5.8 De Morgan's Laws (Already proved in section 3.3)
(A∪B)′=A′∩B′
(A∩B)′=A′∪B′
5.9 Involution Law
(A′)′=A
6. Cardinality of Sets
6.1 Cardinal Number
The number of elements in a finite set A is called its cardinal number.
Notation: n(A) or ∣A∣ or card(A)
Examples:
For A={a,b,c,d}, n(A)=4
For B={1,3,5,7,9}, n(B)=5
n(∅)=0
6.2 Inclusion-Exclusion Principle
For Two Sets:
n(A∪B)=n(A)+n(B)−n(A∩B)
Derivation: When we add n(A) and n(B), elements in A∩B are counted twice. So we subtract n(A∩B) once to count them only once.
Example: Let A={1,2,3,4},B={3,4,5,6}
n(A)=4,n(B)=4
A∩B={3,4},n(A∩B)=2
A∪B={1,2,3,4,5,6},n(A∪B)=6
Verify: 6=4+4−2
For Three Sets:
n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(C∩A)+n(A∩B∩C)
Example: In a survey of 100 students:
60 like Math (M)
50 like Science (S)
40 like English (E)
30 like Math and Science
20 like Science and English
15 like Math and English
10 like all three
How many like at least one subject?
Solution: n(M∪S∪E)=60+50+40−30−20−15+10=95
So 95 students like at least one subject.
6.3 Cardinality Formulas
n(A−B)=n(A)−n(A∩B)
n(A△B)=n(A)+n(B)−2n(A∩B)
n(A′)=n(U)−n(A)
n(A×B)=n(A)⋅n(B)
n(P(A))=2n(A)
7. Cartesian Product
7.1 Definition
The Cartesian product of two sets A and B is the set of all ordered pairs (a, b) where a ∈ A and b ∈ B.
Notation: A×B
Formal Definition: A×B={(a,b):a∈A and b∈B}
Important:
(a,b) is an ordered pair, so (a,b)=(b,a) unless a = b
A×B=B×A in general
7.2 Examples
Let A={1,2},B={a,b} A×B={(1,a),(1,b),(2,a),(2,b)} B×A={(a,1),(a,2),(b,1),(b,2)} Clearly, A×B=B×A
R×R=R2 (the Cartesian plane)
If A=∅ or B=∅, then A×B=∅
7.3 Number of Elements
If A has m elements and B has n elements, then A×B has m×n elements.
Proof: For each of the m elements in A, we can pair it with any of the n elements in B.
Example: For A={1,2,3} (m=3) and B={a,b} (n=2): n(A×B)=3×2=6
7.4 Properties of Cartesian Product
Non-commutative: A×B=B×A (unless A = B or one is empty)
Non-associative: (A×B)×C=A×(B×C)
Distributive over union: A×(B∪C)=(A×B)∪(A×C)
Distributive over intersection: A×(B∩C)=(A×B)∩(A×C)
Distributive over difference: A×(B−C)=(A×B)−(A×C)
7.5 Cartesian Product of Three or More Sets
For sets A, B, C: A×B×C={(a,b,c):a∈A,b∈B,c∈C}
Number of elements: n(A×B×C)=n(A)⋅n(B)⋅n(C)
Example: A={1,2},B={a,b},C={x,y} A×B×C={(1,a,x),(1,a,y),(1,b,x),(1,b,y),(2,a,x),(2,a,y),(2,b,x),(2,b,y)} Total elements = 2×2×2=8
8. Solved Examples
Example 1: Basic Set Operations
Let U={1,2,3,4,5,6,7,8},A={2,4,6,8},B={3,6,7,8}
Find:
A∪B
A∩B
A−B
B−A
A′
A△B
Solution:
A∪B={2,3,4,6,7,8}
A∩B={6,8}
A−B={2,4}
B−A={3,7}
A′=U−A={1,3,5,7}
A△B=(A−B)∪(B−A)={2,4}∪{3,7}={2,3,4,7}
Example 2: Cardinality Problem
In a class of 50 students:
30 like Mathematics
25 like Physics
20 like Chemistry
15 like Mathematics and Physics
10 like Physics and Chemistry
8 like Mathematics and Chemistry
5 like all three subjects
Find:
How many like at least one subject?
How many like exactly one subject?
How many like none of the subjects?
Solution: Let M, P, C represent sets of students liking Mathematics, Physics, Chemistry respectively.
Given: n(U)=50,n(M)=30,n(P)=25,n(C)=20 n(M∩P)=15,n(P∩C)=10,n(M∩C)=8,n(M∩P∩C)=5
Using inclusion-exclusion: n(M∪P∪C)=30+25+20−15−10−8+5=47 So 47 students like at least one subject.
Students liking exactly one subject:
Only M: n(M)−n(M∩P)−n(M∩C)+n(M∩P∩C)=30−15−8+5=12
Only P: n(P)−n(M∩P)−n(P∩C)+n(M∩P∩C)=25−15−10+5=5
Only C: n(C)−n(M∩C)−n(P∩C)+n(M∩P∩C)=20−8−10+5=7 Total = 12 + 5 + 7 = 24 students
Students liking none: n(U)−n(M∪P∪C)=50−47=3
Example 3: Set Algebra Proof
Prove that A−(B∪C)=(A−B)∩(A−C)
Proof: Let x∈A−(B∪C) Then x∈A and x∈/(B∪C) ⇒x∈A and x∈/B and x∈/C ⇒x∈A and x∈/B and x∈A and x∈/C ⇒x∈(A−B) and x∈(A−C) ⇒x∈(A−B)∩(A−C) Thus, A−(B∪C)⊆(A−B)∩(A−C)
Conversely, let x∈(A−B)∩(A−C) Then x∈A−B and x∈A−C ⇒x∈A and x∈/B and x∈A and x∈/C ⇒x∈A and x∈/B and x∈/C ⇒x∈A and x∈/(B∪C) ⇒x∈A−(B∪C) Thus, (A−B)∩(A−C)⊆A−(B∪C)
Therefore, A−(B∪C)=(A−B)∩(A−C)
9. Practice Tips for Exams
Venn Diagrams: Always draw Venn diagrams for visualization
Set Notation: Be precise with notation: ∈,⊆,⊂,∪,∩,∖,△
Cardinality Formulas: Memorize inclusion-exclusion principle
Proof Techniques: For proofs, use element method (show x∈LHS⇒x∈RHS and vice versa)
Special Cases: Remember edge cases: empty set, universal set, disjoint sets
Order Matters: Remember A×B=B×A and A−B=B−A
This comprehensive coverage includes all aspects of Set Theory with detailed explanations and examples, providing a solid foundation for solving MCQs and complex problems in the entrance examination.