# 2.2 MCQs-Complex Numbers

## Complex Numbers

### Basic Concepts and Definitions

1\. A complex number is generally expressed in the form:

1. a + ib, where a and b are real numbers
2. (a, b), where a and b are real numbers
3. reiθ, where r ≥ 0 and θ is real
4. All of the above

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**Answer:** 4. All of the above

**Explanation:**

* Complex numbers can be represented in multiple equivalent forms:
  * **Rectangular/Cartesian form**: z = a + ib, where a = Re(z) and b = Im(z)
  * **Ordered pair form**: z = (a, b)
  * **Polar form**: z = r(cosθ + i sinθ) = reiθ, where r = |z| and θ = arg(z)
* Each form has its advantages for different operations.

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2\. The imaginary unit i is defined as:

1. √(-1)
2. -√(-1)
3. Both 1 and 2
4. √(1)

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**Answer:** 1. √(-1)

**Explanation:**

* The imaginary unit i satisfies i² = -1
* By convention, i = √(-1)
* Note that (-i)² = (-1)² × i² = 1 × (-1) = -1 as well, so -i is also a square root of -1
* In complex numbers, every non-zero number has two square roots

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3\. The complex conjugate of z = 3 - 4i is:

1. 3 + 4i
2. -3 + 4i
3. -3 - 4i
4. 4 - 3i

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**Answer:** 1. 3 + 4i

**Explanation:**

* The complex conjugate of z = a + ib is denoted as (\bar{z}) or z\* and is defined as (\bar{z} = a - ib)
* For z = 3 - 4i, the conjugate is (\bar{z} = 3 + 4i)
* Geometrically, conjugation reflects the complex number across the real axis
* Properties: (\overline{z + w} = \bar{z} + \bar{w}), (\overline{zw} = \bar{z} \cdot \bar{w}), (\overline{z/w} = \bar{z}/\bar{w})

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4\. The modulus of z = 3 + 4i is:

1. 3
2. 4
3. 5
4. 7

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**Answer:** 3. 5

**Explanation:**

* The modulus (or absolute value) of z = a + ib is |z| = √(a² + b²)
* For z = 3 + 4i: |z| = √(3² + 4²) = √(9 + 16) = √25 = 5
* Geometrically, |z| represents the distance from the origin to the point representing z in the complex plane
* Properties: |zw| = |z||w|, |z/w| = |z|/|w|, |z|² = z(\bar{z})

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### Operations on Complex Numbers

5\. If z₁ = 2 + 3i and z₂ = 1 - 2i, then z₁ + z₂ equals:

1. 3 + i
2. 3 + 5i
3. 1 + 5i
4. 3 - i

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**Answer:** 1. 3 + i

**Explanation:**

* Addition of complex numbers is done by adding real parts and imaginary parts separately
* z₁ + z₂ = (2 + 3i) + (1 - 2i) = (2 + 1) + (3i - 2i) = 3 + i
* Geometrically, addition corresponds to vector addition in the complex plane
* Subtraction is similar: z₁ - z₂ = (2 - 1) + (3i - (-2i)) = 1 + 5i

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6\. If z₁ = 2 + 3i and z₂ = 1 - 2i, then z₁ × z₂ equals:

1. 8 - i
2. 8 + i
3. -4 + 7i
4. -4 - i

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**Answer:** 1. 8 - i

**Explanation:**

* Multiplication follows distributive law: (a + ib)(c + id) = ac + iad + ibc + i²bd = (ac - bd) + i(ad + bc)
* z₁ × z₂ = (2 + 3i)(1 - 2i) = 2×1 + 2×(-2i) + 3i×1 + 3i×(-2i)
* \= 2 - 4i + 3i - 6i² = 2 - i - 6(-1) = 2 - i + 6 = 8 - i
* In polar form: multiplication multiplies moduli and adds arguments

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7\. The multiplicative inverse of z = 3 + 4i is:

1. 3 - 4i
2. (3 - 4i)/25
3. (3 + 4i)/25
4. (-3 - 4i)/25

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**Answer:** 2. (3 - 4i)/25

**Explanation:**

* The multiplicative inverse of z = a + ib is 1/z = (\bar{z})/|z|²
* For z = 3 + 4i: |z|² = 3² + 4² = 9 + 16 = 25
* (\bar{z}) = 3 - 4i
* Therefore, 1/z = (3 - 4i)/25
* Verification: (3 + 4i) × (3 - 4i)/25 = (9 + 16)/25 = 25/25 = 1

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### Polar Form and De Moivre's Theorem

8\. The polar form of z = 1 + i√3 is:

1. 2(cos(π/3) + i sin(π/3))
2. 2(cos(π/6) + i sin(π/6))
3. √2(cos(π/3) + i sin(π/3))
4. √2(cos(π/6) + i sin(π/6))

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**Answer:** 1. 2(cos(π/3) + i sin(π/3))

**Explanation:**

* For z = 1 + i√3: a = 1, b = √3
* Modulus: r = √(1² + (√3)²) = √(1 + 3) = √4 = 2
* Argument: θ = tan⁻¹(b/a) = tan⁻¹(√3/1) = tan⁻¹(√3) = π/3 (since point is in first quadrant)
* Polar form: z = r(cosθ + i sinθ) = 2(cos(π/3) + i sin(π/3))
* Exponential form: z = 2e^(iπ/3)

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9\. De Moivre's theorem states that for any integer n:

1. (cosθ + i sinθ)^n = cos(nθ) + i sin(nθ)
2. (cosθ + i sinθ)^n = n(cosθ + i sinθ)
3. (cosθ + i sinθ)^n = cosθ + i sin(nθ)
4. (cosθ + i sinθ)^n = cos(nθ) + sin(nθ)

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**Answer:** 1. (cosθ + i sinθ)^n = cos(nθ) + i sin(nθ)

**Explanation:**

* De Moivre's theorem: (cosθ + i sinθ)^n = cos(nθ) + i sin(nθ) for any integer n
* This follows from Euler's formula: e^(iθ) = cosθ + i sinθ, so (e^(iθ))^n = e^(inθ) = cos(nθ) + i sin(nθ)
* The theorem is useful for:
  * Finding powers of complex numbers
  * Finding roots of complex numbers
  * Expressing cos(nθ) and sin(nθ) in terms of powers of cosθ and sinθ

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10\. The cube roots of unity are:

1. 1, ω, ω² where ω = (-1 + i√3)/2
2. 1, -1, i
3. 1, i, -i
4. 1, ω, ω² where ω = (1 + i√3)/2

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**Answer:** 1. 1, ω, ω² where ω = (-1 + i√3)/2

**Explanation:**

* The cube roots of unity satisfy z³ = 1
* They are: 1, ω = e^(2πi/3) = cos(2π/3) + i sin(2π/3) = (-1 + i√3)/2
* and ω² = e^(4πi/3) = cos(4π/3) + i sin(4π/3) = (-1 - i√3)/2
* Properties: 1 + ω + ω² = 0, ω³ = 1, ω² = (\bar{ω})
* The roots are equally spaced on the unit circle at angles 0°, 120°, 240°

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### Roots of Complex Numbers

11\. The square roots of -4 are:

1. ±2i
2. ±2
3. ±4i
4. ±√2(1 + i)

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**Answer:** 1. ±2i

**Explanation:**

* To find square roots of -4: solve z² = -4
* Let z = a + ib, then (a + ib)² = a² - b² + 2iab = -4
* Equating real and imaginary parts: a² - b² = -4 and 2ab = 0
* From 2ab = 0: either a = 0 or b = 0
* If b = 0: a² = -4 ⇒ no real solution
* If a = 0: -b² = -4 ⇒ b² = 4 ⇒ b = ±2
* Therefore z = ±2i
* Verification: (2i)² = 4i² = 4(-1) = -4, (-2i)² = 4i² = -4

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12\. The fourth roots of 16 are:

1. ±2, ±2i
2. ±4, ±4i
3. 2, 2i, -2, -2i
4. 4, 4i, -4, -4i

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**Answer:** 3. 2, 2i, -2, -2i

**Explanation:**

* Solve z⁴ = 16
* In polar form: 16 = 16e^(i·0) = 16e^(i·2πk) for any integer k
* Using De Moivre: z = 16^(1/4) e^(i·2πk/4) = 2 e^(i·πk/2) for k = 0, 1, 2, 3
* k = 0: z = 2e^0 = 2
* k = 1: z = 2e^(iπ/2) = 2(cos(π/2) + i sin(π/2)) = 2i
* k = 2: z = 2e^(iπ) = 2(cosπ + i sinπ) = -2
* k = 3: z = 2e^(i3π/2) = 2(cos(3π/2) + i sin(3π/2)) = -2i
* The roots are equally spaced on a circle of radius 2 at 90° intervals

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### Complex Plane and Geometry

13\. In the complex plane, |z - z₀| = r represents:

1. A straight line
2. A circle with center z₀ and radius r
3. An ellipse with foci at 0 and z₀
4. A parabola

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**Answer:** 2. A circle with center z₀ and radius r

**Explanation:**

* |z - z₀| represents the distance between complex numbers z and z₀
* The equation |z - z₀| = r means: "all points z whose distance from z₀ is r"
* This is exactly the definition of a circle with center z₀ and radius r
* Example: |z - (3 + 4i)| = 5 is a circle centered at 3 + 4i with radius 5

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14\. The equation |z - 1| = |z + i| represents:

1. A circle
2. A straight line
3. An ellipse
4. A hyperbola

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**Answer:** 2. A straight line

**Explanation:**

* |z - 1| = distance from z to 1 (point (1, 0) on real axis)
* |z + i| = |z - (-i)| = distance from z to -i (point (0, -1) on imaginary axis)
* The equation |z - 1| = |z + i| means: "all points equidistant from (1, 0) and (0, -1)"
* This is the perpendicular bisector of the segment joining (1, 0) and (0, -1)
* In coordinate form: √((x-1)² + y²) = √(x² + (y+1)²)
* Squaring: (x-1)² + y² = x² + (y+1)²
* Expanding: x² - 2x + 1 + y² = x² + y² + 2y + 1
* Simplifying: -2x = 2y ⇒ y = -x, which is a straight line

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### Euler's Formula and Exponential Form

15\. Euler's formula states that:

1. e^(iθ) = cosθ + i sinθ
2. e^(iθ) = cosθ - i sinθ
3. e^(θ) = cosθ + i sinθ
4. e^(iθ) = sinθ + i cosθ

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**Answer:** 1. e^(iθ) = cosθ + i sinθ

**Explanation:**

* Euler's formula: e^(iθ) = cosθ + i sinθ
* This is one of the most important formulas in mathematics
* Consequences:
  * e^(iπ) = cosπ + i sinπ = -1 (Euler's identity: e^(iπ) + 1 = 0)
  * e^(iπ/2) = i
  * e^(2πi) = 1
* The formula connects exponential, trigonometric, and complex number theories

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16\. The exponential form of z = 2(cos(π/4) + i sin(π/4)) is:

1. 2e^(iπ/4)
2. e^(2iπ/4)
3. 2e^(π/4)
4. e^(2π/4)

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**Answer:** 1. 2e^(iπ/4)

**Explanation:**

* For z = r(cosθ + i sinθ), the exponential form is z = re^(iθ)
* Here r = 2, θ = π/4
* Therefore, z = 2e^(iπ/4)
* The exponential form is particularly useful for multiplication, division, and exponentiation:
  * Multiplication: r₁e^(iθ₁) × r₂e^(iθ₂) = (r₁r₂)e^(i(θ₁+θ₂))
  * Division: (r₁e^(iθ₁))/(r₂e^(iθ₂)) = (r₁/r₂)e^(i(θ₁-θ₂))
  * Exponentiation: (re^(iθ))^n = r^n e^(inθ)

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### Applications and Properties

17\. The real part of (1 + i)^4 is:

1. 0
2. -4
3. 4
4. 8

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**Answer:** 2. -4

**Explanation:**

* Method 1: Direct expansion (1 + i)² = 1 + 2i + i² = 1 + 2i - 1 = 2i (1 + i)⁴ = \[(1 + i)²]² = (2i)² = 4i² = 4(-1) = -4 So Re((1 + i)⁴) = -4
* Method 2: Polar form 1 + i = √2 e^(iπ/4) (1 + i)⁴ = (√2)^4 e^(iπ) = 4 e^(iπ) = 4(cosπ + i sinπ) = 4(-1 + 0i) = -4

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18\. If z is a complex number such that |z| = 1, then 1/z equals:

1. z
2. -z
3. (\bar{z})
4. -(\bar{z})

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**Answer:** 3. (\bar{z})

**Explanation:**

* For any complex number z, we have z(\bar{z}) = |z|²
* If |z| = 1, then z(\bar{z}) = 1
* Therefore, 1/z = (\bar{z})
* Example: If z = cosθ + i sinθ = e^(iθ), then |z| = 1
* (\bar{z}) = cosθ - i sinθ = e^(-iθ) = 1/z
* This property is useful in many trigonometric identities and signal processing applications

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19\. The locus of points satisfying arg(z) = π/4 is:

1. A circle
2. A straight line
3. A ray from the origin
4. A line segment

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**Answer:** 3. A ray from the origin

**Explanation:**

* arg(z) = θ means the argument (angle) of z is θ
* In polar coordinates: z = re^(iθ) with r > 0, θ fixed
* This represents all points on the ray starting at the origin and making angle θ with the positive real axis
* Specifically, arg(z) = π/4 represents the ray y = x with x > 0 (first quadrant)
* Note: The origin itself is excluded since arg(0) is undefined

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20\. The triangle inequality for complex numbers states:

1. |z₁ + z₂| ≤ |z₁| + |z₂|
2. |z₁ + z₂| ≥ |z₁| + |z₂|
3. |z₁ + z₂| = |z₁| + |z₂|
4. |z₁ + z₂| ≤ ||z₁| - |z₂||

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**Answer:** 1. |z₁ + z₂| ≤ |z₁| + |z₂|

**Explanation:**

* Triangle inequality: |z₁ + z₂| ≤ |z₁| + |z₂| for all complex numbers z₁, z₂
* Geometrically: In any triangle, the length of one side is less than or equal to the sum of the lengths of the other two sides
* Equality occurs when z₁ and z₂ have the same argument (are in the same direction)
* Reverse triangle inequality: |z₁ - z₂| ≥ ||z₁| - |z₂||
* These inequalities are fundamental in analysis and have many applications

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