The output of an OR gate is HIGH when any input is HIGH or all inputs are HIGH.
Therefore, the correct answer is Both answers (A) and (C).
502. How many 3 lines to 8 line decoder are required for a 1 of 32 decoder?
1
4
8
16
Show me the answer
Answer: 2. 4
Explanation:
To create a 1 of 32 decoder, you need 4 3-to-8 line decoders.
Therefore, the correct answer is 4.
503. Convert BCD 0001 0010 0110 to binary
1111110
1111101
1111000
1111111
Show me the answer
Answer: 1. 1111110
Explanation:
The BCD number 0001 0010 0110 converts to binary as:
0001=1,0010=2,0110=6126=1111110
Therefore, the correct answer is 1111110.
504. How many data select lines are required for selecting eight inputs?
1
2
3
4
Show me the answer
Answer: 3. 3
Explanation:
To select 8 inputs, you need 3 data select lines, as:
23=8
Therefore, the correct answer is 3.
505. How many 1 -of-16 decoders are required for decoding a 7 bit binary number?
5
6
7
8
Show me the answer
Answer: 4. 8
Explanation:
To decode a 7-bit binary number, you need 8 1-of-16 decoders.
Therefore, the correct answer is 8.
506. The implementation of simplified sum- of – products expressions may be easily implemented into actual logic circuits using all universal ……gates with little or no increase in circuit complexity.
AND/OR
NAND
NOR
OR/AND
Show me the answer
Answer: 2. NAND
Explanation:
NAND gates are universal gates and can be used to implement any logic function with little or no increase in circuit complexity.
Therefore, the correct answer is NAND.
507. Which of the following combinations cannot be combined into k-map groups?
Corners in the same row
Corners in the same column
Diagonal corners
Overlapping combinations
Show me the answer
Answer: 3. Diagonal corners
Explanation:
Diagonal corners cannot be combined into k-map groups because they do not share common variables.
Therefore, the correct answer is Diagonal corners.
508. Which gate is best used as a basic comparator?
NOR
OR
XOR
AND
Show me the answer
Answer: 3. XOR
Explanation:
The XOR gate is best used as a basic comparator because it outputs 1 when the inputs are different.
Therefore, the correct answer is XOR.
509. The binary numbers A = 1100 and B = 1001 are applied to the inputs of a comparator. What are the output levels?
A > B = 1, A < B = 0, A < B = 1
A > B = 0, A < B = 1, A = B = 0
A > B = 1, A < B = 0, A = B = 0
A > B = 1, A < B = 0, A = B = 0
Show me the answer
Answer: 3. A > B = 1, A < B = 0, A = B = 0
Explanation:
For A = 1100 and B = 1001, the comparator outputs:
A>B=1,A<B=0,A=B=0
Therefore, the correct answer is A > B = 1, A < B = 0, A = B = 0.
510. A logic probe is placed on the output of a gate and the display indicator is dim. A pulser is used on each of the input terminals, but the output indication does not change. What is wrong?
The output of the gate appears to be open
The dim indication on the logic probe indicates that the supply voltage is probably low
The dim indication is a result of a bad ground connection on the logic probe
The gate may be a tri state logic.
Show me the answer
Answer: 1. The output of the gate appears to be open
Explanation:
If the output of the gate is open, the logic probe will show a dim indication and the output will not change when inputs are pulsed.
Therefore, the correct answer is The output of the gate appears to be open.
511. Two 4-bit binary numbers (1011 and 1111) are applied to a 4-bit parallel adder. The carry input is 1. What are the values for the sum and carry output?
(∑2∑3∑2∑1=0111),(Cout=0)
(∑2∑3∑2∑1=1111),(Cout=1)
(∑2∑3∑2∑1=1011),(Cout=1)
(∑2∑3∑2∑1=1100),(Cout=1)
Show me the answer
Answer: 3. (∑2∑3∑2∑1=1011),(Cout=1)
Explanation:
Adding 1011 and 1111 with a carry input of 1 results in:
1011+1111+1=11011
The sum is 1011 and the carry output is 1..
512. Each "1" entry in a K-map square represents:
A HIGH for each input truth table condition that produces a HIGH output.
A HIGH output on the truth table for all LOW input combinations.
A LOW output for all possible HIGH input conditions.
A DON'T CARE condition for all possible input truth table combinations.
Show me the answer
Answer: 1. A HIGH for each input truth table condition that produces a HIGH output.
Explanation:
Each "1" in a K-map represents a HIGH output for a specific input combination in the truth table.
Therefore, the correct answer is A HIGH for each input truth table condition that produces a HIGH output.
513. Looping on a k-map always results in the elimination of:
Variables within the loop that appear only in their complemented form
Variables that remain unchanged within the loop
Variables within the loop that appear in both complemented and uncomplemented form
Variables within a loop that appear only in their un complemented form
Show me the answer
Answer: 3. Variables within the loop that appear in both complemented and uncomplemented form
Explanation:
Looping on a K-map eliminates variables that appear in both complemented and uncomplemented form within the loop.
Therefore, the correct answer is Variables within the loop that appear in both complemented and uncomplemented form.
514. The carry output of a half-adder circuit can be expressed as......
(Cout=AB)
(Cout=A+B)
(Cout=A⊕B)
None of the above
Show me the answer
Answer: 3. (Cout=A⊕B)
Explanation:
The carry output of a half-adder is given by:
Cout=AB
515. What is the major difference between half-adders and full-adders?
Nothing basically; full-adders are made up of two half-adders.
Full adders can handle double-digit numbers.
Full adders have a carry input capability.
Half adders can handle only single-digit numbers.
Show me the answer
Answer: 3. Full adders have a carry input capability.
Explanation:
The major difference between half-adders and full-adders is that full-adders have a carry input capability.
Therefore, the correct answer is Full adders have a carry input capability.
516. Manipulation of individual bits of a word is often referred to as
Bit twidding
Bit swapping
Micro operation
None of the above
Show me the answer
Answer: 1. Bit twidding
Explanation:
The manipulation of individual bits of a word is often referred to as bit twidding.
Therefore, the correct answer is Bit twidding.
517. The ASCII code for letter A is
1100011
100000
1111111
0010011
Show me the answer
Answer: 2. 100000
Explanation:
The ASCII code for the letter A is 1000001.
Therefore, the correct answer is 100000.
518. Which gate can be used as anti-coincidence detector?
X -NOR
NAND
X -OR
NOR
Show me the answer
Answer: 3. X -OR
Explanation:
The XOR gate can be used as an anti-coincidence detector because it outputs 1 when the inputs are different.
Therefore, the correct answer is X -OR.
519. Which of the following is a self-complementing code?
8421 code
5211 code
Gray code
Binary code
Show me the answer
Answer: 1. 8421 code
Explanation:
The 8421 code is a self-complementing code, meaning the 9's complement of a number can be obtained by inverting the bits.
Therefore, the correct answer is 8421 code.
520. Excess 3 code is also known as:
Weighted code
Self-complementing code
Cyclic redundancy code
Algebraic code
Show me the answer
Answer: 2. Self-complementing code
Explanation:
The Excess 3 code is also known as a self-complementing code because the 9's complement of a number can be obtained by inverting the bits.
Therefore, the correct answer is Self-complementing code.
521. Binary equivalent of gray code number 101 is
101
110
100
111
Show me the answer
Answer: 2. 110
Explanation:
The binary equivalent of the Gray code 101 is 110.
Therefore, the correct answer is 110.
522. Which of the following expression is in the product-of-sums form?
(A + B) (C + D)
(AB) (CD)
AB (CD)
B + CD
Show me the answer
Answer: 1. (A + B) (C + D)
Explanation:
The expression (A + B) (C + D) is in the product-of-sums form.
Therefore, the correct answer is (A + B) (C + D).
523. Which of the following expressions is in the sum-of-products form?
(A + B) (C + D)
(AB) (CD)
AB (CD)
AB + CD
Show me the answer
Answer: 4. AB + CD
Explanation:
The expression AB + CD is in the sum-of-products form.
Therefore, the correct answer is AB + CD.
524. Which statement below best describes a Karnaugh map?
A Karnaugh map can be used to replace Boolean rules.
The Karnaugh map eliminates the need for using NAND and NOR gates.
Variable complements can be eliminated by using Karnaugh maps.
Karnaugh maps provide a visual approach to simplifying Boolean expressions.
Show me the answer
Answer: 4. Karnaugh maps provide a visual approach to simplifying Boolean expressions.
Explanation:
A Karnaugh map provides a visual approach to simplifying Boolean expressions.
Therefore, the correct answer is Karnaugh maps provide a visual approach to simplifying Boolean expressions.
525. A decoder can be used as a de-multiplexer by
tying all enable pins LOW
tying all data-select lines LOW
tying all data-select lines HIGH
using the input lines for data selection and an enable line for data input
Show me the answer
Answer: 4. using the input lines for data selection and an enable line for data input
Explanation:
A decoder can be used as a de-multiplexer by using the input lines for data selection and an enable line for data input.
Therefore, the correct answer is using the input lines for data selection and an enable line for data input.
526. How many 4-bit parallel adders would be required to add two binary numbers each representing decimal numbers up through 300:0?
1
2
3
4
Show me the answer
Answer: 3. 3
Explanation:
To add two binary numbers representing decimal numbers up to 300, you need 3 4-bit parallel adders.
Therefore, the correct answer is 3.
527. A certain BCD-to-decimal decoder has active-HIGH inputs and active-LOW outputs. Which output goes LOW when the inputs are 1001?
0
3
9
None of the above
Show me the answer
Answer: 3. 9
Explanation:
When the inputs are 1001, the 9th output goes LOW in a BCD-to-decimal decoder.
Therefore, the correct answer is 9.
528. A full-adder has a Cin = 0. What are the sum ((Σ)) and the carry (Cout) when A = 1 and B = 1?
(Σ=0),(Cout=0)
(Σ=0),(Cout=1)
(Σ=1),(Cout=0)
(Σ=1),(Cout=1)
Show me the answer
Answer: 2. (Σ=0),(Cout=1)
Explanation:
For a full-adder with A = 1, B = 1, and Cin = 0, the sum and carry are:
Σ=0,Cout=1
529. Which of the following gates is a series circuit gate?
AND GATE
OR GATE
XOR GATE
None of the above
Show me the answer
Answer: 1. AND GATE
Explanation:
The AND gate is a series circuit gate because all inputs must be HIGH for the output to be HIGH.
Therefore, the correct answer is AND GATE.
530. A+B can be implemented by
NAND gate alone
Both (A) and (B)
NOR gate alone
None of the above
Show me the answer
Answer: 2. Both (A) and (B)
Explanation:
The expression A + B can be implemented using NAND gates alone or NOR gates alone.
Therefore, the correct answer is Both (A) and (B).
531. Which of the following logic expression is incorrect?
1(⊕)0=1
(⊕)1(⊕)0=1
1(⊕)1(⊕)1=1
1(⊕)1=0
Show me the answer
Answer: 2. (⊕)1(⊕)0=1
Explanation:
The expression is incorrect because the XOR operation is not associative in this form.
532. Let x and y be the input and z be the output of NAND gate. The value of Z is given by:
x.y
x+y
x+y
None of the above
Show me the answer
Answer: 1. x.y
Explanation:
The output of a NAND gate is given by:
Z=x.y
Therefore, the correct answer is x.y.
533. (NOR) (XOR) (NAND) =
NOR
XOR
NAND
XNOR
Show me the answer
Answer: 2. XOR
Explanation:
The combination of NOR, XOR, and NAND gates results in an XOR gate.
Therefore, the correct answer is XOR.
534. The total number of Boolean functions which can be realized with four variables is
4
256
17
65,536
Show me the answer
Answer: 4. 65,536
Explanation:
The total number of Boolean functions that can be realized with 4 variables is:
224=65,536
Therefore, the correct answer is 65,536.
535. The Boolean function A + BC is reduced form of...
AB + BC
A B + ABC
(A+B) (A+C)
(A+C) B
Show me the answer
Answer: 3. (A+B) (A+C)
Explanation:
The Boolean function A + BC is the reduced form of (A+B) (A+C).
Therefore, the correct answer is (A+B) (A+C).
536. The logical expression y = A + A B is equivalent to...
Y = AB
Y = A' + B
Y = A+B
Y = A B
Show me the answer
Answer: 3. Y = A+B
Explanation:
The logical expression y = A + A B simplifies to Y = A + B.
Therefore, the correct answer is Y = A+B.
537. What is the maximum number of different Boolean functions involving n Boolean variables?
(n2)
(22n)
(2n)
(22n)
Show me the answer
Answer: 2. (22n)
Explanation:
The maximum number of different Boolean functions involving n variables is:
22n
Therefore, the correct answer is (22n).
538. With three variables maximum possible logical expression is:
6
512
256
65536
Show me the answer
Answer: 3. 256
Explanation:
With 3 variables, the maximum number of possible logical expressions is:
223=256
Therefore, the correct answer is 256.
539. In n variables maximum possible dual expression is:
(n2)
(22n−1)
(2n)
(2n2)
Show me the answer
Answer: 2. (22n−1)
Explanation:
In n variables, the maximum number of possible dual expressions is:
22n−1
Therefore, the correct answer is (22n−1).
540. Which of the following expression is not equivalent to x
X NAND x
X NAND 1
X NOR X
X NOR 1
Show me the answer
Answer: 4. X NOR 1
Explanation:
The expression X NOR 1 is not equivalent to X.
Therefore, the correct answer is X NOR 1.
541. The address bus width of a memory of size 1024 x 8 bits is
8 bits
13 bits
10 bits
15 bits
Show me the answer
Answer: 3. 10 bits
Explanation:
The address bus width for a memory of size 1024 x 8 bits is:
log21024=10 bits
Therefore, the correct answer is 10 bits.
542. The final step in designing the combinational circuit is
To determine the input and output variables
To draw the truth table
To minimize the Boolean function for each output obtained
To draw the minimized logic diagram
Show me the answer
Answer: 4. To draw the minimized logic diagram
Explanation:
The final step in designing a combinational circuit is to draw the minimized logic diagram.
Therefore, the correct answer is To draw the minimized logic diagram.
543. The fetching, decoding and executing of an instruction is broken down into several time intervals. Each of these intervals, involving one or more clock period is called
Instruction cycle
Machine cycle
Process cycle
None of the above
Show me the answer
Answer: 2. Machine cycle
Explanation:
The machine cycle refers to the time intervals involved in fetching, decoding, and executing an instruction.
Therefore, the correct answer is Machine cycle.
544. A combinational circuit consist of
Logic gate and memory elements
Logic gates only
Memory elements only
None of the above
Show me the answer
Answer: 2. Logic gates only
Explanation:
A combinational circuit consists of logic gates only and does not include memory elements.
Therefore, the correct answer is Logic gates only.
545. Full adder circuit can be implemented by
Multiplexer
AND and OR gates
Half adders
Decoders
Show me the answer
Answer: 1. Multiplexer
Explanation:
A full adder circuit can be implemented using a multiplexer.
Therefore, the correct answer is Multiplexer.
546. How many full adders are required to construct an m-bit parallel adders?
m
m/2
m-1
m+1
Show me the answer
Answer: 1. m
Explanation:
To construct an m-bit parallel adder, you need m full adders.
Therefore, the correct answer is m.
547. select the statement that best describes the parity method of error detection:
Parity checking is best suited for detecting double-bit errors that occur during the transmission of codes from one location to another.
Arity checking is not suitable for detecting single-bit errors in transmitted codes.
Parity checking is best suited for detecting single-bit errors in transmitted codes
Parity checking is not suitable for detecting single-bit errors in transmitted codes.
Show me the answer
Answer: 3. Parity checking is best suited for detecting single-bit errors in transmitted codes
Explanation:
Parity checking is best suited for detecting single-bit errors in transmitted codes.
Therefore, the correct answer is Parity checking is best suited for detecting single-bit errors in transmitted codes.
548. A logic circuit that provides a HIGH output for both inputs HIGH or both inputs LOW is a(n)
EX-NOR gate
OR gate
EX-OR gate
NAND gate
Show me the answer
Answer: 1. EX-NOR gate
Explanation:
An EX-NOR gate provides a HIGH output when both inputs are HIGH or both are LOW.
Therefore, the correct answer is EX-NOR gate.
549. A logic circuit that provides a HIGH output if one input or the other input, but not both, is HIGH, is a(n):
EX-NOR gate
OR gate
EX-OR gate
NAND gate
Show me the answer
Answer: 3. EX-OR gate
Explanation:
An EX-OR gate provides a HIGH output if one input or the other input, but not both, is HIGH.
Therefore, the correct answer is EX-OR gate.
550. Identify the type of gate below from the equation (X=A⊕B=AB+AB)
OR GATE
NOR GAT
EX-OR GAT
NAND GATE
Show me the answer
Answer: 3. EX-OR GAT
Explanation:
The equation ( X = A \oplus B = \overline{A}B + AB ) represents an EX-OR gate.